tag:blogger.com,1999:blog-2400513859305780710.post5447592362105697157..comments2023-04-04T07:53:53.789-07:00Comments on Mathematical Food For Thought: Mean. Topic: Algebra/Probability & Combinatorics/Calculus. Level:
Olympiad.Jeffrey Wanghttp://www.blogger.com/profile/11114458640271201663noreply@blogger.comBlogger2125tag:blogger.com,1999:blog-2400513859305780710.post-38816370021904762332007-02-05T14:36:06.000-08:002007-02-05T14:36:06.000-08:00Your solution seems a little complicated; why not ...Your solution seems a little complicated; why not simply multiply together the geometric means of all k-subsets at a time? Then it's clear that every element appears equally often, and it's also clear that the expression is of the right degree of homogeneity (by induction).t0rajir0unoreply@blogger.comtag:blogger.com,1999:blog-2400513859305780710.post-85368346214334992742007-02-05T15:34:43.000-08:002007-02-05T15:34:43.000-08:00You are very tricksy... that's almost what I d...You are very tricksy... that's almost what I did anyway, though. I just did a lot of explaining to arrive at the solution. And as I said, I didn't make many symmetry arguments =).paladin8noreply@blogger.com