tag:blogger.com,1999:blog-2400513859305780710.post5681701860683136165..comments2023-04-04T07:53:53.789-07:00Comments on Mathematical Food For Thought: Distasteful Distance. Topic: Sequences & Series. Level: AIME.Jeffrey Wanghttp://www.blogger.com/profile/11114458640271201663noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-2400513859305780710.post-91715892181661304822019-05-16T18:24:02.030-07:002019-05-16T18:24:02.030-07:00sdesdeTEACHERLOOKUP. COMhttps://www.blogger.com/profile/15136106087852689252noreply@blogger.comtag:blogger.com,1999:blog-2400513859305780710.post-14256058961862013712007-01-28T12:29:48.000-08:002007-01-28T12:29:48.000-08:00I wouldn't be surprised if the summation you p...I wouldn't be surprised if the summation you posted telescoped. Consider that min({ k/6n}, {k/3n}) is definitely related to min({(6n-k)/6n}, {(6n-k)/3n}).t0rajir0unoreply@blogger.comtag:blogger.com,1999:blog-2400513859305780710.post-73914874960091331912007-01-28T12:50:25.000-08:002007-01-28T12:50:25.000-08:00I think they're equal. So you would just sum t...I think they're equal. So you would just sum the first half... not that big of a difference o_O.paladin8noreply@blogger.comtag:blogger.com,1999:blog-2400513859305780710.post-11768923433779312472007-01-29T13:24:54.000-08:002007-01-29T13:24:54.000-08:00Anyway, the problem you posted is n by induction. ...Anyway, the problem you posted is n by induction. You prove that only one of the expressions changes when n increments by 1.t0rajir0unoreply@blogger.com